10log125 + 10log6 + 10log2- 10log3 -10log5

10log 125 + 10log 6 + 10log 2 - 10log 3 - 10log 5
=10log 125 + 10log 6 + 10log 2 - (10log 3 +10log 5)
= 10log ([tex] \frac{125*6*2}{3*5} [/tex])
= 10log [tex] \frac{1500}{15} [/tex]
= 10log 100
= 2

==Jawaban==

Harap diingat !
ᵃlogb + ᵃlogc = ᵃlog(b.c)
ᵃlogb - ᵃlogc = ᵃlog(b/c)
ᵃlogbⁿ = n.ᵃlogb
ᵃloga = 1

Jadi,,
¹⁰log125 + ¹⁰log6 + ¹⁰log2 - ¹⁰log3 - ¹⁰log5
= ¹⁰log(125.6) + ¹⁰log2 - ¹⁰log3 - ¹⁰log5
= ¹⁰log750 + ¹⁰log2 - ¹⁰log3 - ¹⁰log5
= ¹⁰log(750.2) - ¹⁰log3 - ¹⁰log5
= ¹⁰log1500 - ¹⁰log3 - ¹⁰log5
= ¹⁰log(1500/3) - ¹⁰log5
= ¹⁰log500 - ¹⁰log5
= ¹⁰log(500/5)
= ¹⁰log100
= ¹⁰log10²
= 2.¹⁰log10
= 2.1
= 2