Matematika

Pertanyaan

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Tolong bntu jwb kka...pakai cara!

1 Jawaban

  • luas bangun ABCD ( jajar genjang) = 2 luas segitiga BCD
    [tex]t = \sqrt{ {10}^{2} - {6}^{2} } \\ = \sqrt{64} = 8[/tex]
    =
    [tex] = 2 \: \frac{ (a \times t)}{2} \\ = a \times t \\ = 12 \times 8 = 96[/tex]

    luas bangun AEB (segitiga)
    [tex]t = \sqrt{ {13}^{2} - {5}^{2} } \\ t = \sqrt{169 - 25} \\ t = \sqrt{144} \\ t = 12[/tex]
    [tex] \frac{a \times t}{2} \\ \frac{10 \times 12}{2} = 60[/tex]

    = 98+60
    =156 cm