Hitung y' dari : ln^2 lnx tolooong

jawab

y = ln² (ln x)

t= ln (ln x)
dt/dx =  1/(x. ln x)

y = t²
dy/dt = 2 t 

y' = dy/dx
dy/dx = dy/dt. dt/dx
y' = (2t)/(x . ln x)
y' = (2 ln(ln x) ) / (x . ln x)