tolong bantuin soal no 1.
Matematika
silvia248
Pertanyaan
tolong bantuin soal no 1.
1 Jawaban
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1. Jawaban evaisal
[tex] \frac{( {5x}^{4} {y}^{ - 3}) ^{ - 3} }{( {5x}^{5} {y}^{ - 2}) ^{3} } = \frac{ {5x}^{ - 12} {y}^{ 9}}{ {5x}^{15} {y}^{ - 6} } \\ = \frac{ {5x}^{12} {y}^{6} }{ {5x}^{15} {y}^{9}} \\ = {5x}^{ - 3} {y}^{ - 3} \\ = \frac{1}{ {5x}^{3} {y}^{3} } [/tex]
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