persamaan garis yang melalui titik (2,5) dan tegak lurus garis x - 4y - 11 = 0 adalah

Diket :
x-4y-11 = 0
x1 = 2
y1 = 5

Jawab :
x-4y-11 = 0
x-11 = 4y
1/4x-11/4 = y
m1 = 1/4

m1.m2 = -1
m2 = -1/1/4
m2 = -4

y-y1 = m(x-x1)
y-5 = -4(x-2)
y = -4x+8+5
y = -4x+13

Maaf jika ada kesalahan :)

KELAS VIII
MATERI : PERSAMAAN GARIS LURUS

=============JAWABAN===============

* Tegak Lurus
[tex]x - 4y - 11 = 0 \\ - 4y = - x + 11 \\ y = \frac{ - x}{ - 4} - \frac{11}{4} \\ \\ m = \frac{1}{4} [/tex]
* Persamaan Garis
[tex]y - y1 = m(x - x1) \\ y - 5 = \frac{1}{4} (x - 2) \\ 4(y - 5) = x - 2 \\ 4y - 20 = x - 2 \\ 4y - 20 - x + 2 = 0 \\ \\ 4y - x - 18 = 0[/tex]

note: please make the best answer