nilai x yang memenuhi persamaan ^2 log^2 (2x-2) - ^2 log (2x-2)= 2 adalah...

²log² (2x - 2) - ²log (2x - 2) = 2
²log² (2x - 2) - ²log (2x - 2) - 2 = 0

Misal :
²log (2x - 2) = a

a² - a - 2 = 0
(a + 1)(a - 2) = 0
a = -1 atau a = 2

utk a = -1
²log (2x - 2) = -1
2x - 2 = 2^-1
2x = 1/2 + 2
2x = 5/2
x = 5/4

utk a = 2
²log (2x - 2) = 2
2x - 2 = 2²
2x = 4 + 2
x = 6/2
x = 3

NiLai x yg memenuhi :
5/4 dan 3