tolong dijawab ya.. 1sampai 8 aja beserta jalannya.. tolong banget...

jwab
1)
(x² -1) / (x² -2x + 1) =
= (x  -1)( x+ 1)  / (x - 1)(x -1)
= ( x +1)/(x - 1)

2)
(2x² - 3x - 9) / (4x² - 9) = 
= (2x + 3)(x + 3) / (2x + 3)(2x -3)
= (x  +3)/(2x - 3)  

3)
(2x² - 5x - 3)/ (6x² - x - 2) =
= (2x + 1)(x - 3) / (2x +1)(3x -2)
= (x - 3)/(3x -2)

4)
(p² - p  -6)/ (9 - p²) = 
= (p - 3)(p+2) ./ (3-p)(3 +p)
= -(p+2)/(p+3)

5)
(x+y)²  - (x-y)² =
= (x +y + x - y)(x + y - x + y)
= (2x)(2y)
= 4 xy

6) 
1/(a+b)  + 1/(a-b) =
= (a - b + a + b)/(a +b)(a -b)
= 2a/(a² - b²)


7) 
2/( x-1)  - 3/(x +2) = 
= 2(x+2) - 3( x -1) / (x-1)(x+2)
= (2x + 4 - 3x +3)// (x²  +x - 2)
=(5x+ 7)/(x² + x - 2)

8)
(x-1)/(x² -4) - 1/(x -2) = 
= (x- 1 - 1(x +2)) / (x² - 4)
= (x - 1 - x - 2)/(x² -4)
= - 3/(x² -4)