jika p=1/2,q=2/5,dan r=3/4 selesaikan bentuk dibawah ini a.(r)³+p×q b.(p+r)×√(q)² c.(r-p)×q d.(4/3q×5/2p)+r

[tex]p = \frac{1}{2} \\ q = \frac{2}{5} \\ r = \frac{3}{4} [/tex]
a. r³ + pq
(¾)³ + (½)(2/5) = (27/64) + (2/10)
= (135/320 + 64/320)
= 199/320

b. (p+r) √(q)²
(p+r)q = (½+¾)×(2/5)
=(5/4)(2/5)
= ½

c. (r-p) q
(¾-½)×(2/5)
= ½ × (2/5)
= 1/5

d. (4/3q. 5/2p) + r
((4/3)(2/5)(5/2)(1/2)) + ¾
= ⅔ + ¾
= 17/12