jawab pertanyaanq kanda dinda mo di kumpul sebentar

[tex]1. \: {125}^{ \frac{2}{3} } - {64}^{ \frac{1}{4} } + {81}^{ \frac{3}{4} } \\ = {5}^{3 \times \frac{2}{3} } - {2}^{6 \times \frac{1}{4} } + {3}^{4 \times \frac{3 }{4} } \\ = {5}^{2} - {2}^{ \frac{6}{4} } + {3}^{3} \\ = 25 + 9 - \sqrt[4]{64} \\ = 34 - 2 \sqrt{4} [/tex]

[tex]2. \: 4 \sqrt{27} + 2 \sqrt{75} - 3 \sqrt{48} + 5 \sqrt{12} \\ = 4 \sqrt{3.3.3} + 2 \sqrt{3.5.5} - 3 \sqrt{2.2.2.2.3} + 5 \sqrt{2.2.3} \\ = 4.3 \sqrt{3} + 2.5 \sqrt{3} - 3.2.2 \sqrt{3} + 5.2 \sqrt{3} \\ = 12 \sqrt{3} + 10 \sqrt{3} - 12 \sqrt{3} + 10 \sqrt{3} \\ = 20 \sqrt{3} [/tex]
[tex]3. \: \frac{2}{2 \sqrt{2} + \sqrt{5} } . \frac{2 \sqrt{2} - \sqrt{5} }{2 \sqrt{2} - \sqrt{5} } \\ = \frac{4 \sqrt{2} - 2\sqrt{5} }{8 - 5} \\ = \frac{4 \sqrt{2} - 2 \sqrt{5} }{3} [/tex]
[tex]4. \: 2log3 - 2log24 + 2log16 \\ = 2log( \frac{3 \times 16}{24} ) \\ = 2log2 \\ = 1[/tex]
Maaf kalo salah, semoga membantu
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