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jawab

f(x)= (1/3)ˣ

pada interval  -3≤ x ≤ 3
x = -3, -2, -1, 0, 1, 2, 3

f(-3) = (1/3)⁻³ =  (3⁻¹)⁻³ = 3³ = 27 --> A(-3, 27)
f(-2) = (1/3)⁻² = (3⁻¹)⁻² = 3² = 9 --> B (-2, 9)
f(-1) = (1/3)⁻¹ = (3⁻¹)⁻¹ = 3¹ = 3 --> C (-1, 3)
f(0)  = (1/3)⁰ = 1 --> D (0,1)
f(1)  = (1/3)¹ = 1/3 --> E (1, 1/3)
f(2) = (1/3)² = 1/9  --> F (2, 1/9)
f(3) = (1/3)³ = 1/27 --> G(3, 1/27)

A,B,C,D,E,F dan G buat di kartesius, hubungkan semua titik