persamaan kuadrat x^2 + px + q = 0 mempunyai akar x1 dan x2, dengan x1 - x2 = -1.jika x1 + 1 dan x2 juga akar persamaan kuadrat x^2 +(p-1)x + q +2 =0, maka p+q=

jawab

x² + px + q = 0
x1+x2 = -p
x1 x2 = q

(x1 - x2 ) = 1
(x1 - x2)² = 1²
(x1 + x2)² - 4 x1x2 = 1
p²- 4q = 1.....(i)

x² +(p-1)x + (q +2)= 0 akar nya x1+1 dan x2

x1+1 + x2 = -(p-1)
x1+x2 = 1 - p  - 1
p = p

(x1 +1)(x2) = q+2
x1x2 + x2= q + 2
q + x2 = q + 2
x2 = 2

x1 - x2 = -1
x1 - 2 = -1
x1 = 1


p+q = -(x1+x2)+ (x1 x2)
p + q = -(1 +2) + (1)(2)
P + q = - 3 + 2
p + q = - 1